
How to find duplicate values in SQL Table?
Let's see how to find duplicate values in an SQL table.
Problem
Let’s see how to find duplicate values in an SQL table.
Input
| id | name | enrollment_number |
|---|---|---|
| 1 | Alice | ENR123 |
| 2 | Bob | ENR124 |
| 3 | Charlie | ENR125 |
| 4 | David | ENR123 |
| 5 | Edward | ENR126 |
| 6 | Frank | ENR124 |
Try Hands-On: Fiddle
Create Source tables: Code Gist
Desired Output
| enrollment_number | count |
|---|---|
| ENR123 | 2 |
| ENR124 | 2 |
Solution 1:
Using GROUP BY
sql
SELECT enrollment_number, COUNT(enrollment_number) as count
FROM students
GROUP BY enrollment_number
HAVING count >1;
Explanation:
GROUP BYenrollment_number: This will create groups of rows based on unique enrollment_number values.HAVING count >1: This is a post-grouping filter that allows us to only consider those groups where the count of enrollment_number is more than 1. Hence, it filters the groups to show only the duplicates.COUNT(enrollment_number) as count: This will count the number of occurrences of each enrollment_number in the grouped result.
Solution 2:
Using correlated subquery
sql
SELECT name, enrollment_number
FROM students
WHERE enrollment_number IN (
SELECT enrollment_number
FROM students
GROUP BY enrollment_number
HAVING COUNT(enrollment_number) > 1
);
Result:
| name | enrollment_number |
|---|---|
| Alice | ENR123 |
| Bob | ENR124 |
| David | ENR123 |
| Frank | ENR124 |
Explanation:
The inner query (subquery) selects all the enrollment_numbers that have a count greater than 1, thus identifying duplicates.
The outer query then filters the main table, students, to show only rows where the enrollment_number matches one from the list identified as duplicates in the subquery.
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